Check the CBSE Class 10 Maths Extra Questions for Chapter 5 - Arithmetic Progression to prepare more effectively for your board exam. All the extra questions are very simple and useful to revise the important concepts used in the chapter. Practicing with these questions will help you to learn the application of the various AP formulae in different problems. Therefore, solve all the extra questions to give an edge to your preparations and achieve desired marks in the exam.
Check CBSE Class 10 Maths Extra Questions and Answers for Chapter 5 - Arithmetic Progression:
Q. Common difference of an A.P. can be
(i) Positive
(ii) Negative
(iii) Zero
(iv) All of the above
Answer:
(iv) All of the above
Q. Write the general form of an AP.
Answer:
The general form of an AP is a, a + d, a + 2d, a + 3d, . . .
where a is the first term and d the common difference.
Q. In the following AP find the value of k.
100, 85, 70, (k + 20), 40, 25, .....
Answer:
k = 35
Hint: Here, common difference, d = -15
(k + 20) - 70 = -15
Q. Which term of the AP: 21, 18, 15, . . . is 0?
Answer:
Eighth term of the AP is 0.
Hint: Let nth term be 0, then
a + (n - 1)d = 0
Also Check:
NCERT Solutions for Class 10 Maths
Q. Find the nth term of an AP the sum of whose r terms is 3r2 + 4r.
Answer:
nth term, an = 6n + 1
Hint: Given, Sr = 3r2 + 4r
an = Sn − Sn−1
= 3n2 + 4n − (3(n − 1)2 + 4(n − 1))
Q. Find the number of terms of the AP −10, −6, −2, 2, 6, ....that add up to give the sum 1140.
Answer:
30 terms of the AP −10, −6, −2, 2, 6, ..... add up to give the sum 1140.
Hint: Let the required number of terms be n. Then,
Note: While making the exam preparations, students should go through the Revised CBSE Syllabus for Class 10 Maths so that they can avoid the deleted topics and prepare according to the topics that are prescribed by the board.
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