IICB Recruitment 2019: Walk in for 58 JRF Posts
Indian Institute of Chemical Biology is hiring 58 JRF Posts
IICB Jobs 2019: CSIR – Indian Institute of Chemical Biology (CSIR-IICB) is conducting walk in interview for the post of Junior Research Fellow on 03 June 2019.
Walk-in-Interview - 03 June 2019 (Monday) from 09.30 a.m. - 10.30 a.m.
Indian Institute of Chemical Biology Vacancy Details
JRF (Direct) - 58 Posts (Chemistry, Organic, Inorganic and Bio organic Chemistry, Synthetic Organic Chemistry, Medicinal Chemistry, Chemical Biology, Nanomaterial & their characterization by biological studies, Metal catalysis, Neurobiology and Cancer Biology, Bioinformatics, Structural Biology, Infectious Diseases & Immunology, Plant Sciences, Biotechnology, Molecular Genetics, Cell Biology or any branch of Life Sciences)
Eligibility Criteria for JRF Posts
NET-JRF (CSIR/UGC) examination qualified candidates or DBT/DST-INSPIRE/ICMR-JRF Fellows having independent fellowship with M.Sc degree in Chemistry / Biology. Students in their final year of M.Sc may also apply, provided they fulfil other qualifications.
How to Apply for Indian Institute of Chemical Biology Jobs 2019
Eligible candidates may appear for the Walk-in-Interview on 03 June 2019 (09.30 a.m. - 10.30 a.m.) at the J.C. Ray Auditorium, Jadavpur Campus.