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Maharashtra Board Class 12 Chemistry Solved Question Paper 2017

Dec 10, 2018 16:12 IST
    Maharashtra Board Class 12 Chemistry Solved Question Paper 2017
    Maharashtra Board Class 12 Chemistry Solved Question Paper 2017

    Here we are bringing the Maharashtra Board Class 12 Chemistry Solved Question Paper 2017. Solutions have been collated in the form of PDF which students may download to check the right criteria to write perfect exam and score high marks.

    Maharashtra Board Class 12 Chemistry Solved Question Paper will not only help students to know the important questions but also to write proper explanation to them. All these solutions are designed in the simplest way to help students easily understand the concepts and facts used.

    Key features of Maharashtra Board Class 12 Chemistry Solved Question Paper 2017 are

    • Simple and stepwise solutions are provided for each question
    • Appropriate concepts have been used in solutions
    • Chemical equations are written correctly

    A few sample questions and their solutions are given below:

    Q. What are ‘fuel cells’? Write cathode and anode reaction in a fuel cell.

    Ans.

    Galvanic cells which use energy of combustion of fuels like H2, CH4, CH3OH, etc., as the source to produce electrical energy are called fuel cells. The fuel cells are pollution free and have high efficiency.

    Cell reaction :

    At anode: 2H2(g) + 4OH (aq) → 4H2O(l) + 4e

    At cathode: O2(g) + 2H2O(l) + 4e → 4OH (aq)

    Q. viii. Write the electronic configuration of the following elements:

    a. Sulphur (Z = 16)                  b.   Krypton (Z = 36)

    Ans.

    Sulphur (Z = 16): 1s2 2s2 2p6 3s2 3p4

    Krypton (Z = 36): 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6

    Maharashtra State Board HSC Chemistry Syllabus, Pattern and Marks Allotment

    Q. 0.05 M NaOH solution offered a resistance of 31.6W in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm-1, calculate the molar conductivity of NaOH solution.

    Ans.

     maharashtra hsc chemistry 2017

    Q. What is ‘effective atomic number’ (EAN)?

    Calculate the effective atomic number of the central metal atom in the following compounds:

    a. K4Fe(CN)6 Fe (Z = 26)

    b. Cr(CO)6 Cr (Z = 24)

    Ans.

    The sum of the number of electrons, donated by all ligands and those present on the central metal ion or atom in complex is called as effective atomic number (EAN).

    EAN = [Atomic number of metal, Z – (Oxidation state of the metal, O) + 2(Coordination number of the metal, C)].

    a. K4Fe(CN)6 Fe (Z = 26)

    Z = 26, O = +2, C = 6

    EAN = Z − X + 2 × Y = 26 – 2 + (2 × 6) = 36

    b. Cr(CO)6 Cr (Z = 24)

    Z = 24, O = 0 , C = 6

    EAN = Z − X + 2 × Y = 24 + (2 × 6) = 36

    To download the completely solved paper, click on the following link:

    Maharashtra Board Class 12 Chemistry Solved Question Paper 2017

    To get more of such important articles for Maharashtra Board Class 12 Board Exams 2019, click here.

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