Jagran Josh Logo
  1. Home
  2. |  
  3. CBSE Board|  

CBSE Class 12 Physics NCERT Exemplar Solutions: Chapter 10 – Wave Optics

May 28, 2018 17:15 IST
    CBSE Class 12 Physics NCERT Exemplar Solutions
    CBSE Class 12 Physics NCERT Exemplar Solutions

    Find NCERT Exemplar Solutions for all the questions of Class 12 Physics Chapter 10 – Wave Optics here. These questions are very important for competitive exams like IIT JEE (JEE Main and JEE Advanced), UPSEE, WBJEE, VITEEE, SRMJEEE and NEET etc., as the difficulty level of these questions is quite higher. These solutions are explained by experienced Subject Experts of Physics.

    Important Topics of Chapter 10 – Waves Optics:

    • Huygen's principle,
    • Reflection and refraction of plane wave at a plane surface using wave fronts,
    • Proof of laws of reflection and refraction using Huygens’s principle,
    • Interference and Young's double slit experiment and expression for fringe width,
    • Coherent sources and sustained interference of light,
    • Diffraction due to a single slit,
    • Width of central maximum,
    • Resolving power of microscopes and astronomical telescopes,
    • Polarisation,
    • Plane polarised light,
    • Brewster's law and
    • Uses of plane polarised light and Polaroids

    Types and number of questions in this chapter:

    Types

    Number of questions

    MCQ I (Multiple choice questions with single correct option)

    5

    MCQ II (Multiple choice questions with multiple correct options)

    4

    VSA (Very short answer type questions)

    6

    SA (Short answer type questions)

    3

    LA (Long answer type questions)

    5

    Total

    23

    Few problems and their solutions from this chapter are given below:

    Question:

    In a Young's double-slit experiment, the source is white light. One of the holes is covered by a red filter and another by a blue filter. In this case,

    (a) There shall be alternate interference patterns of red and blue

    (b) There shall be an interference pattern for red distinct from that for blue

    (c) There shall be no interference fringes

    (d) There shall be an interference pattern for red mixing with one for blue

    Solution:(c)

    We know that, for the interference pattern to be formed on the screen, the sources should be coherent and emits lights of same frequency and wavelength.

    In a Young's double-slit experiment, if one of the holes is covered by a red filter and another by a blue filter, then only red and blue lights are present due to alteration. In Young's double-slit experiment, a monochromatic light is used for the formation of fringes on the screen.

    Therefore, there shall be no interference fringes.

    Question:

    Consider sunlight incident on a pinhole of width 103 Å. The image of the pinhole seen on a screen shall be

    (a) A sharp white ring

    (b) Different from a geometrical image

    (c) A diffused central spot, white in colour

    (d) Diffused coloured region around a sharp central white spot

    Solution: (b, d)

    We are given that, the width of pinhole is 103 Å or 1000 Å

    We know that, the wavelength of visible sunlight lies between 4000 Å and 8000 Å.

    Since, the wavelength (l) is less than the width of the slit.

    Hence, the light is diffracted from the hole.

    Due to diffraction the image formed on the screen will be different from the geometrical image.

      Related Video: What is NIOS?

    Question:

    Consider the diffraction pattern for a small pinhole. As the size of the hole is increased

    (a) The size decreases                               

    (b) The intensity increases

    (c) The size increases                                

    (d) The intensity decreases

    Solution: (a, b)

    (a) The width of central maximum of diffraction pattern of hole is inversely proportional to the size of the hole.

    Therefore, the width (size) of central maximum decreases when size of the hole increases.

    (b) Since, the amount of light energy distributed over a small area is same.

    Hence, the intensity will increase.

    Question:

    Why is the diffraction of sound waves more evident in daily experience than that of light wave?

    Solution:

    The diffraction occurs only if the wavelength of waves and width of the slit is almost equal.

    But we know that, the frequencies of sound waves lie between 20 Hz and 20000 Hz. Therefore, the range of their wavelength is between 15 m and 15mm.

    Now, the wavelength of light waves is 7000 × 10-10 m to 4000 × 10-10 m. The width of the slit is very near to the wavelength of sound waves as compared to light waves. This is the reason why the diffraction of sound waves is more evident in daily life than that of light waves.

    CBSE Class 12 Physics NCERT Exemplar Solutions: Chapter 8 – Electromagnetic Waves

    Link to Download NCERT Exemplar Solutions for Class 12 Physics: Chapter 10 – Wave Optics

    Types of Question

    Link to Download PDF

    5 MCQ I (Multiple choice questions with single correct option)

    Download Link

    4 MCQ II (Multiple choice questions with multiple correct options)

    Download Link

    6 VSA (Very short answer type questions)

    Download Link

    3 SA (Short answer type questions)

    Download Link

    5 LA (Long answer type questions)

    Download Link

    Latest Videos

    Register to get FREE updates

      All Fields Mandatory
    • (Ex:9123456789)
    • Please Select Your Interest
    • Please specify

    • By clicking on Submit button, you agree to our terms of use
      ajax-loader
    • A verifcation code has been sent to
      your mobile number

      Please enter the verification code below

    Newsletter Signup
    Follow us on
    X

    Register to view Complete PDF